A doctor in Michigan has a sister who lives in California but the sister does not have any brother that lives in Michigan, how come??
:P

Back to the 60 L container question.
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Slackdemic's solution:

1. Pour the mixture from the original container (60 L) to 7 L container and transfer that 7 L to 43 L container. Repeat it.

At this point, the 43 L container has 14 L of oil.

2. Now, the trickiest part: Pour the oil from the original container to 11 L container. And, pour the 11 L container, which is full, to 7 L container. Now the 11 L container has 4 L oil (11-7=4).

3.Pour that 4 L water to the 43 L container where there is already 14 L of oil. Now it is altogether 18 L of oil in 43 L container.

4. Repeat step #2 three more times, which will result in 12 L of oil (4*3=12)!!! So altogether 18 + 12 = 30 L of oil in 43 L Container. And, at the same time 30 L of water is left in the original 60 L container.
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I thought you had got it right at first glance. But then I got suspicious because your solution has no need for the 43 L container. I couldn't figure out where the flaw was in your solution for a while, but I do now.

You cannot repeat steps 2 & 3 three times as you have suggested.

Let's say you did it one more time and added 4 L of oil to the 43 L container. Now you have 22 L of oil there. You pour the 7L of oil back into the original container, which now has 30L water and 8L oil.

What next? When you repeat step 2 again, you have 8 L of oil and 3 L of water in the 11 L container. When you pour that into the 7L container.. you have 1 L of oil and 3L of water left - NOT 4 L of oil.

Still trying to work out the solution.

Ritthe, haven't tried Einstein one- this one is enough for now... back to work time :(,

will try later

republican that has laready been solved my juggy i think ....... try other one posted few threads above and the one if einstien

I think I've worked it out! But I still don't understand why the 43L container is there, could there be a shorter/better solution?

Basically I've used a combination of 7s and 11s that add up to 30 :

11 + 11 + 11 + 11 - 7 - 7 = 30

So

1. Pour from 60L to 11L and then to 43L container - you have 11 liters oil in the 43L container now.

2. Pour from 60L to 11L and then to 43L container again - now you have 22 liters oil in the 43L container.

3. Now pour from 43L to 7L to 60L container - you have 15 liters oil in the 43L container.

4. Again, pour from 43L to 7L to 60L container - you have 8 liters of oil in the 43L container.


That means you have 22 liters of oil in the 60L container now. Repeat step 1 twice (pour 11 liters twice into the 43L container) and you have 30L oil in the 43L container.

ritthe, juggy's solution used a non-existent "bottom" of the container :) I tried to solve it without assuming that.

wuts up azn, long time no see.....

sadbut true i need the answers from you...for the math test..

Here's one:

You have two containers of the same size - one is filled with milk and the other is filled with the exact same amount of water. Let's say Container A has milk and Container B has water.

You take one cup of milk from Container A and mix it in Container B.

Then you take one cup of the milk/water mixture in Container B and mix it in Container A.

Considering that milk and water is evenly distributed when mixed, does Container A have more water or does Container B have more milk?

.hehe Republican!! I agree to disagree with my solution, But It seems Paradox has already solved that one up there!! I tried to elaborate his solution though!!
But it is good to see you using your brain too!! Brain damage it is!!
and republican can u be more clearer!! The Container A has milk and Container B has water. But were they completely full??...:S..:S
Have a good one everyone!!..:)

Republican,

Container A water=Container B milk

right??

Brilliantly done, Republican! I admire your logic! :)

Yes, the same night I thought I solved the riddle, I asked one of my friends if she could solve it, and when trying to explain how it could be solved, I found I was mistaken myself. Yes, until third step, it works okay, then it doesn't.

Well, you did it, now I don't see the necessity of doing it another way, if there is. Also, I am still confused what is the necessity of 43L jar; any big jar just works fine, innit?

I even haven't read the other question posted by you; I will try to do it if it is interesting. :)

juggy, the containers are not full but the amount of milk in A and water in B are equal.

hetterika, you could be right : ) i'd like to see the logic behind it though, that's the interesting part, isn't it?

slackdemic, i think the 43L is just to throw you off a little.. maybe the solution would be easier if it was any other amount. Or if the question said "any big jar", you'd probably be able to find the answer sooner.

if the containers contained exaclty a cupfull of liquid, the concentration of the milk will be equal in both containers but if the volume was more than a cupfull, the concentration of the milk will be more in the container which contained milk initally when the process was started.

12 – 12 = 12 – 12
(1 + 1) (1 – 1) = (1 – 1)
(1 + 1) = 1
2 = 1
Why is it not possible?

they r not 12, 1 raised to power 2, 1^2

the concentration of milk in A would be greater because you are mixing some milk (that went from A to B, and taking a part of it back to A) to a lower amount in A.

so what i think is if you are talking about the amount, it would be tha same as in your question but if it is to do with the concentration, there would be a difference (the other way round in your question).

just a try hai.

ritthe
in your third line, you cannot have 1 on your RHS

ratamakai,

(1 - 1) in both sides cancel each other thats why 1 there.

Doctor in Michigan has a sister in california, sister means nurse. But the sister has no brother. Doctor is not her brother. Simple.

no (1-1) is 0 and you cannot cancel two zeros,
a zero canceled (or divided lets say) by another zero is never 1