A doctor in Michigan has a sister who lives in California but the sister does not have any brother that lives in Michigan, how come??
:P

There are three married couples that need to cross a river. A small boat is available that will hold just two people at a time. The males involve are quite jealous. No woman can be left with a man unless her husband is also present. There are no other constraints, though. How can these six people cross the river?

Even challanging, what is the fewest number of trips possible?

View/Share this post only

1. A couple on first trip.
2. Husband returns back
3. Another couple on second trip, the frst wife returns back.
4. Brings her husband, leaves him and returns back again.
5. Third Couple on third trip, both stay there and the first husband returns back
6. Picks his wife on fourth trip

Don't have much of brain remaining, its already thursday. :-)

"Don't have much of brain remaining, its already thursday. :-)"

You gotta have some more, because that logic didn't work, Camo! ;) Please read the problem again and see if you can find what you missed.

1. First couple on first trip, first wife stays on the other bank and husband returns
2. Second Couple on second trip, second wife stays there and husband returns
3. First husband and second husband on third trip, first husband stays there and second couple returns.
4. second and third husband on 4th trip, both stay and the first wife returns
5. second wife and first wife on 5th trip, both stay and third husband returns
6. Third couple on 6th trip.

Pheww!!!

No more energy now!! tired.

Oops! Still didn't work.

OK this took a while. I don't know if this is the shortest solution.

1st couple - H1 W1
2nd couple - H2 W2
3rd couple - H3 W3

1. H1 and W1 cross to the other side.

h2 w2 h3 w3 ----- h1 w1

2. H1 comes back.

h1 h2 w2 h3 w3 ----- w1

3. W2 and W3 cross.

h1 h2 h3 ----- w1 w2 w3

4. W1 comes back.

h1 w1 h2 h3 ----- w2 w3

5. H2 and H3 cross.

h1 w1 ----- h2 w2 h3 w3

6. H2 and W2 come back.

h1 w1 h2 w2 ----- h3 w3

7. H1 and H2 cross.

w1 w2 ----- h1 h2 h3 w3

8. W3 comes back.

w1 w2 w3 ----- h1 h2 h3

9. W1 and W2 cross.

w3 ------ h1 w1 h2 w2 h3

10. W1 comes back.

w1 w3 ----- h1 h2 w2 h3

11. W1 and W3 cross.

nobody left ----- h1 w1 h2 w2 h3 w3

A bear falls into a hole. The length of the hole is 5 meter and it takes the bear 1 second to reach the bottom.
What is the color of the bear?

Hey Golvenda, the color of bear is always black.

Bear could be brown too.

Republican, how neatly you did it! You got it right. And, yes, the fewest number of trips (=shortest solution) possible is 11. Well done. :)

.lol, I was way off last night. ha ha ha!!

See I told you, it's hard to concentrate in Thursday evening and it is impossible in Friday Evening. You see what I mean, slackdemic bro? :-)

Have a good one!!

:-)

Ah, Camo bro, I think I know what you mean. :P :D

How about the same problem with four couples, for this Friday afternoon. I know it could be tedious, but here's the hint: don't try too long only to be bored to tears or angry to fist to someone. :P

Now I hope you know what I mean. ;)

Republican, you may also want to give it a try. The same hint applies to you too. :)

Golveda, I think the falling of bear to the hole or the radius of the size of the hole doesn't change the original color of bear, no?

solve the Reimann hypothesis instead

Alright you all smart people: here is your problem, solve this is you can.
Keith numbers are fibonacchi like numbers where you sum up first few number and then those digits reappear in a subsequent sums. eg:
1 , 4 , 5, 9 , 14
2, 8 , 10, 18, 28

now find the number that is 30 digits long

A bear falls into a hole. The length of the hole is 5 meter and it takes the bear 1 second to reach the bottom.
What is the color of the bear?

Frens,
The color of bear can be black , brown or white too.
To solve this problem you need knowledge of physics that you did in your high school.

@Golvenda if by fall you mean nothing pushed the bear into the hole then
i assume initial velocity to be 0. So in 1 second bear can travel 4.4 meteres.
So bear cannot reach the bottom.
If you talk about chance then there is probability of white bear(polar) being able
to do that because the gravity at poles is greater than at other parts of earth.
According to my knowledge it is still impossible because the gravity at poles is
only about 1% higher than at equator.

@jay
he largest known Keith number as of Mar. 31, 2006 is the 29-digit number 70267375510207885242218837404.
I am not gonna find a new one let some of sajhahitis find it:)

Try this:

There are 1000 bottles of water. One of the bottles contains water contaminated with some poison. You have 10 rats for an experiment to find which bottle contains contaminated water. A rat will die within 10 hours of drinking poisonous water. How will you identify the bottle in 10 hours?

gemmi_auj, how many bottles a rat can drink in an hour? Is that given or we are to make our own assumptions?

Golveda, my closed mind doesn't see/find any link between physics and the color of bear on that problem.

Slackdemic, a rat can be made to drink water from any number of bottles in negligible time. The poison will show effect within 10 hours. And there is just 10 hours to find everything. So, rats should be made to drink water samples at the beginning of the 10-hour time.

Hope this clarifies the thing.